x^2-16x-504=0

Solution for x^2-16x-504=0 equation:

x^2-16x-504=0

a = 1; b = -16; c = -504;
Δ = b2-4ac
Δ = -162-4·1·(-504)
Δ = 2272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2272}=\sqrt{16*142}=\sqrt{16}*\sqrt{142}=4\sqrt{142}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{142}}{2*1}=\frac{16-4\sqrt{142}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{142}}{2*1}=\frac{16+4\sqrt{142}}{2}
$